number of atoms of oxygen present in 10.6 gram of Na2co3will be
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No of atoms= given wt/gmwxNa
= 10.6/106x 6.02x 10^23
= 6.02 x 10^22
Hope this helps!!:)
= 10.6/106x 6.02x 10^23
= 6.02 x 10^22
Hope this helps!!:)
vivekkarad:
wrong answer
Can you correct it please?
I’m sorry I didn’t see the oxygen thereee
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