Question

Number of atoms present in 4.25 g of NH3

Answer 1

Hey Buddy.
Here is your solution.
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Molar mass NH3 = 14+3 = 17g/mol
given mass = 4.25g

no of moles = 4.25/17 = 0.25 mol of NH3

1 mol of NH3 contains 6.022*10^23 molecules
0.25 mol NH3 contains 0.25*6.022*10^23 = 1.5055*10^23 molecules

1 molecule of NH3 contains 4 atoms
Number of atoms in 1.5055*10^23 molecules = 4*1.5055*10^23 atoms.

The correct answer is = 6.022*10^23 atoms.
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HOPE YOU GOT IT.
GREETS :)