Question

Number of electrons present in one mole of ch3cooc3h7

Answer 1

Answer:

fkx Iran I I am not sure

6 so ia

Answer 2

(i) 1 mole of methane (CH4) = 1 mole of C + 4 × 1 mole of H
we know,
1 mole of C = 6 mole of electrons
1 mole of H = 1 mole of electron

so, 1 mole of CH4 = 6 + 4 = 10 mole of electrons
but 1 mole = 6.022 × 10²³
so, 1 mole of CH4 = 10 × 6.022 × 10²³ electrons
= 6.022 × 10²⁴ electrons


(ii) given weight of ¹⁴C = 7mg
atomic weight of ¹⁴C = 14 g/mol
so, no of mole = given weight/atomic weight
= 7mg/14g/mol = 0.5 × 10^-3 mol
we know,
number of neutron in one ¹⁴C = 14 - 6 = 8
number of mole of neutrons = no of mole of ¹⁴C × 8 = 0.5 × 10^-3 × 8 = 4 × 10^-3
total number of neutrons = no of mole of neutrons × Avogadro's constant
= 4 × 10^-3 × 6.022 × 10²³
= 24.088 × 10²¹

mass of 24.088 × 10²¹ neutrons = 24.088 × 10²¹ × 1.675 × 10^-27 Kg
= 4.0347 × 10^-6 Kg


(iii) given weight = 34 mg
molecular mass of NH3 = 17 g/mol
no of mole = 34mg/14g/mol = 2 × 10^-3 mol
we know,
1 mole of NH3 = (7 + 3) moles of protons
= 10 moles of protons
so, number of moles of NH3 in 34mg = 10 × 2 × 10^-3 = 2 × 10^-2

number of protons = no of mole of protons × Avogadro's constant
=2 × 10^-2 × 6.022 × 10²³
= 1.2044 × 10²² protons


mass of protons = no of protons × mass of 1 proton
= 1.2044 × 10²² × 1.6726 × 10^-27 Kg
= 2.01447 × 10^-5 Kg

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