number of integers lying between 1 and 100 that are divisible by either 3 or 7
Attachments:
Answers
Answered by
7
No . of Numbers from 1-100 divisible by 3 are =>
99 = 3 + (n-1)3
96 = (n-1)3
n = 33
No. of numbers from 1-100 divisible by 7
98 = 7 + (n1-1)7
n = 14
No. of numbers common in n and n1
84 = 21 + (x-1)21
X = 4
Total numbers which are either divisible by 3 or 7 are (33+14)-4 = 43
99 = 3 + (n-1)3
96 = (n-1)3
n = 33
No. of numbers from 1-100 divisible by 7
98 = 7 + (n1-1)7
n = 14
No. of numbers common in n and n1
84 = 21 + (x-1)21
X = 4
Total numbers which are either divisible by 3 or 7 are (33+14)-4 = 43
Answered by
0
Answer:Secondary School Math 5+3 pts
Number of integers lying between 1 and 100 that are divisible by either 3 or 7
Report by DANISHSURAJ 16.01.2019
Answers
Gourav90982Ambitious
Know the answer? Add it here!
Kundank
KundankExpert
No . of Numbers from 1-100 divisible by 3 are =>
99 = 3 + (n-1)3
96 = (n-1)3
n = 33
No. of numbers from 1-100 divisible by 7
98 = 7 + (n1-1)7
n = 14
No. of numbers common in n and n1
84 = 21 + (x-1)21
X = 4
Total numbers which are either divisible by 3 or 7 are (33+14)-4 = 43
Step-by-step explanation:
Similar questions