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The variation in temperature throughout the day in a desert town was studied on the basis of the records of the
maximum and minimum temperatures which were 36 and 8 degree centigrade respectively. What was the
standard deviation in degree centigrade?
22
14
12
28
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Answered by RvChaudharY50
36

Given :- The variation in temperature throughout the day in a desert town was studied on the basis of the records of the maximum and minimum temperatures which were 36 and 8 degree centigrade respectively. What was the standard deviation in degree centigrade ?

A) 22

B) 14

C) 12

D) 28

Solution :-

Step 1) :- work out the arithmetic mean of the numbers .

  • Total numbers = 2
  • Sum = 36 + 8 = 44
  • Arithmetic mean = Sum / Total numbers = 44/2 = 22.

Step 2) :- Take each number, subtract the mean and square the result .

  • Differences = (36 - 22) = 14, (8 - 22) = (-14). (Every Number minus Mean)
  • (Differences)² = (14)² = 196, (-14)² = 196 (Square of each difference)

Step 3) :- Now calculate the Variance .

  • Sum of (Differences)² = 196 + 196 = 392
  • Variance = (Sum of Differences)² / Total numbers = (392/2) = 196 .

Step 4) :- Take the square root of the Variance .

  • Standard Deviation = √(Variance) = √(196) = 14.

Therefore, standard deviation in degree centigrade was 14. (Option B).

Learn more :-

The mean and standard deviation of a data which is comprised of a set of ten positive numbers are 8 and 2 respectively ....

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