Question

‘O’ is any point in the interior of a triangle ABC. OD ⊥ BC, OE ⊥ AC and OF ⊥ AB, show that
(i) OA² + OB² + OC² − OD² − OE² − OF² = AF² + BD² + CE²
(ii) AF² + BD² + CE² = AE² + CD² + BF².

Answer 1

Answer:

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