O is the centre of the circle, bo is the bisector of angle ABC. show that AB=AC..Please please urgent
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Answered by
8
join OA and OC..
now, in triangle AOB and COB
OB=OB (common)
AO= CO (RADII )
angles r equal (GIVEN)
∴ BY congruence criteria triangles are congruent and AB = AC (BY cpct. )
now, in triangle AOB and COB
OB=OB (common)
AO= CO (RADII )
angles r equal (GIVEN)
∴ BY congruence criteria triangles are congruent and AB = AC (BY cpct. )
Anonymous:
hope it helps
Answered by
3
in triangle about and triangle boc
oa=ocradii
ob=ob common side
abo=boc
by rhs congruence ∆abo=~ ∆boc
by cpct AB=AC
oa=ocradii
ob=ob common side
abo=boc
by rhs congruence ∆abo=~ ∆boc
by cpct AB=AC
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