obtain all zeroes of 3x4-15x3+13x2+25x-30
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12-45+26-750
so the answer is -757
so the answer is -757
vinaygolechha:
ok
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Solution :
Here, f(x)=3x4−15x3+13x2+25x−30
As, 53−−√and−53−−√ are two of the zeroes of the f(x).
∴(x−53−−√)and(x+53−−√) are the factors of f(x).
⇒(x2−53) is the factor of f(x).
Now, we can write,
3x4−15x3+13x2+25x−30=3x2(x2−53)−15x(x2−53)+18(x2−53)
=(x2−53)(3x2−15x+18)
=(3x2−5)(x2−5x+6)
=(3x2−5)(x−2)(x−3)
So, remaining zeroes of f(x) are 2 and 3.
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