Question

of one zeros of p(x)=4x^2-(8k^2-4k)x-9 is negative of the other ,fing the value of k

Answer 1

Let two roots of quadratic equation are x(1) & x(2).

Then according to question,

x(1) = -x(2)

x(1) + x(2) = 0

-(b/a)=0 ( sum of roots = -(coefficient of x / coefficient of x^2) )

8k/4=0

k=0

Answer 2

Let the roots of Zero be a and - a

( coz it is given in the question that the zero of equation are negative of other )


Sum of Zeros =

$\frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }$

$a + ( - a) = \frac{8 {k}^{2} - 4k }{4}$

0 = 8k² - 4k

0 = 2k ( 4k - 2 )

2k = 0
k = 0/2
k = 0


( 4k - 2 ) = 0

k = 2 / 4

k = 1 / 2