Ok rambus perimeter 52cm and diagnal 24cm then area how much
Answers
Answered by
0
Hi friend ✋✋✋✋
--------------
Your answer
-------------------
Perimeter of a rhombus = 52 cm
Measure of each side of the rhombus = 52/4 cm = 13 cm
Measure of one of the diagonals of the rhombus = 24 cm
Let the measure of another diagonal be x.
Then,
-----------
(x/2)² + (24/2)² = (13)²
=> x²/4 + (12)² = 169
=> x²/4 + 144 = 169
=> x²/4 = 169 - 144
=> x² = 25 × 4
=> x² = 100
=> x = √100
=> x = 10 cm
Therefore,
Measure of the other diagonal of the rhombus = 10 cm
So,
------
Area of the rhombus = 1/2 × diagonal 1 × diagonal ×2
= [ 1/2 × 24 × 10] cm²
= 120 cm²
HOPE IT HELPS
--------------
Your answer
-------------------
Perimeter of a rhombus = 52 cm
Measure of each side of the rhombus = 52/4 cm = 13 cm
Measure of one of the diagonals of the rhombus = 24 cm
Let the measure of another diagonal be x.
Then,
-----------
(x/2)² + (24/2)² = (13)²
=> x²/4 + (12)² = 169
=> x²/4 + 144 = 169
=> x²/4 = 169 - 144
=> x² = 25 × 4
=> x² = 100
=> x = √100
=> x = 10 cm
Therefore,
Measure of the other diagonal of the rhombus = 10 cm
So,
------
Area of the rhombus = 1/2 × diagonal 1 × diagonal ×2
= [ 1/2 × 24 × 10] cm²
= 120 cm²
HOPE IT HELPS
Similar questions