Question

Okay! Can you pretty please solve the question number 26!!!!!☃️

Answer 1

Answer:

FVUYFVYV/V/LB

Step-by-step explanation:

Answer 2

Answer:

Put

${e}^{2x } + {e}^{ - 2x} = y \\ (2 {e}^{2x} - 2 {e}^{ - 2x } )dx = dy \\ ( {e}^{2x} - {e}^{ - 2x } )dx = {dy \over \: 2}$

$\int \: \frac{1}{y} \frac{dy}{2} \\ = \frac{1}{2} log( |y| ) + c \\ = \frac{1}{2} log( {e}^{2x } + {e}^{ - 2x} ) + c$

or

To solve second just put tan x = t , and multiply and divide cos x in denominator .