okay what is the sum of even integers? easy question
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The sum of even integer = n(n + 1) / 2
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Answer:
n ( n + 1 )
Step-by-step explanation:
The sum of the first n even integers is
2 + 4 + 6 + ... + 2n
= 2 × ( 1 + 2 + 3 + ... + n )
= 2 × n ( n + 1 ) / 2
= n ( n + 1 )
Example:
The first 3 even integers.
2 + 4 + 6 = 12
n = 3 => n ( n + 1 ) = 3 × 4 = 12
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