Physics, asked by srijatasarkar, 1 year ago

on a level road a scooterist applies brakes to slow down from a speed of 10m/s to 5m/s. If the mass of the scooter and the scooterist be 150kg ,calculate the work done by the brakes. (neglect air resistance and friction).

Answers

Answered by JunaidMirza
261
Work done = Change in Kinetic energy
= 0.5mv² - 0.5mu²
= 0.5m (v² - u²)
= 0.5 × 150 kg × [(5 m/s)² - (10 m/s)²]
= -5625 J
= -5.625 kJ

Work done by brakes is -5.625 kJ
Here negative sign indicates that work is done against the motion of scooter.

JunaidMirza: You're welcome
Answered by mrdilipkatiyar837
46

Answer:

-5625.0 or -5625 j

Explanation:

As we know that,

Work done = Change in kinetic energy

0.5mv^2 = 0.5mu^2

0.5m(v^2-u^2)

0.5*150*-75

37.5*-150

-5625 joules

- ve sign indicates that work is acting on the opposite side of force.

Hope it will help you.

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