Physics, asked by rihanna50, 1 year ago

On closing the switch S in the circuit as shown in the figure, the reading of the galvanometer G

Attachments:

Answers

Answered by zilmil123
2

Answer:

On closing the switch S in the circuit as shown in the figure, the reading of the galvanometer G  Remains same

Explanation:

it is a Balanced wheatstone bridge

 The circuit is a balanced wheatstone bridge and therefore the current through the galvanometer will always be zero.

Answered by Anonymous
7

Refer to the attachment!^^"

Attachments:
Similar questions