Question

on dividing 3y cube + y square+ 2y + 5 by a polynomial gx he the quotient and remainder were 3y_ 5 and 9y + 10 respectively find gx

Answer 1

Answer:

g(x) = y² + 2y + 1

Step-by-step explanation:

divident = 3y³ + y² + 2y + 5

quotient = 3y - 5

reminder = 9y + 10

divisor = ?

divident = divisor × quotient + reminder

3y³+y²+2y+5 = g(x) × (3y - 5) + (9y + 10)

3y³+y²+2y+5 - (9y+10) = g(x) × (3y - 5)

3y³+y²+2y+5 -9y-10 = g(x) × (3y-5)

3y³ + y² - 7y - 5 = g(x) × (3y - 5)

(3y³ + y² -7y - 5)/(3y-5) = g(x)

y² + 2y +1 = g(x)