Question

On heating a glass block of 10000cm from 25c to 45c its volume increases by 4cm calculate coefficient of linear expansion

Answer 1

Answer:

do it practically at home and touch it you feel the hot

• and your face like

Answer 2

The coefficient of linear expansion is $6.6\times10^{-6}/^{\circ}C$

Explanation:

Given that,

Initial temperature = 25°C

Final temperature = 45°C

Volume $V= 10^{4}\ cm^3$

Change in volume $\Delta V=4\ cm^3$

We need to calculate the change in temperature

$\Delta T=T_{f}-T_{i}$

Put the value into the formula

$\Delta T=45-25$

$\Delta T=20^{\circ}C$

We know that,

The coefficient of linear expansion is

$\alpha=\dfrac{\gamma}{3}$...(I)

We need to calculate the coefficient of linear expansion

Using formula of expansion

$\Delta V=V\times\gamma\times\Delta T$

$\gamma=\dfrac{\Delta V}{V\times\Delta T}$

Put the value into the formula

$\gamma=\dfrac{4}{10^4\times20}$

$\gamma=0.00002/^{\circ}C$

Put the value of $\gamma$ in equation (I)

$\alpha=\dfrac{0.00002}{3}$

$\alpha=0.0000066/^{\circ}C$

$\alpha=6.6\times10^{-6}/^{\circ}C$

Hence, The coefficient of linear expansion is $6.6\times10^{-6}/^{\circ}C$

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Topic : coefficient of linear expansion

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