Math, asked by nazisk, 10 months ago

on saturday omkar and shriniwas both eat together finish 25 samosas , and omkar eat more than shriniwas 5 samosa . find how much samosas they both eat separately .

plz right the right answer.


from linear equation .​

Answers

Answered by Anonymous
3

Answer:

here your answer....

Step-by-step explanation:

let omkar eaten by samosas be x

lly srinivas x-5

atq

x+x-5=25

2x=25+5=30

x=30/2=15

therefore

omkar=15 samosas

srinivas=10 samosas

Answered by tushal56
1

Answer:

let the samosa eaten by shrinivas be x.

the samosa eaten by om kar be 5+x

5x + x = 25

5 +2x = 25

2x = 25-5 = 20

x = 20÷2 = 10

so samosas eaten by shrinivas be 10

by om kar be 5 + 10 = 15

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