on saturday omkar and shriniwas both eat together finish 25 samosas , and omkar eat more than shriniwas 5 samosa . find how much samosas they both eat separately .
plz right the right answer.
from linear equation .
Answers
Answered by
3
Answer:
here your answer....
Step-by-step explanation:
let omkar eaten by samosas be x
lly srinivas x-5
atq
x+x-5=25
2x=25+5=30
x=30/2=15
therefore
omkar=15 samosas
srinivas=10 samosas
Answered by
1
Answer:
let the samosa eaten by shrinivas be x.
the samosa eaten by om kar be 5+x
5x + x = 25
5 +2x = 25
2x = 25-5 = 20
x = 20÷2 = 10
so samosas eaten by shrinivas be 10
by om kar be 5 + 10 = 15
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