on selling a tea set at 5% loss and a lemon at 15% gain, a shopkeeper gains rs70. if he sells the tea set at 5% gain and the lemon set at 10% gain, he gains rs130. find the cost price of the lemon set
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Solution:-
Let the cost of tea set be Rs 'x' and the cost of lemon set be Rs 'y'.
The shopkeeper sells a tea set at 5 % loss and a lemon set ate 15 % gain.
So, the loss on tea set = x*5/100
And the gain on lemon set = y*15/100
Total gain = 15y/100 - 5x/100 = 70
15y - 5x = 7000
Dividing it by 5, we get
3y - x = 1400
-x + 3y = 1400...........(1)
If he sells the tea set at 5 % gain and lemon set at 10 % gain, he gains Rs 130.
Therefore,
5x/100 + 10y/100 = 130
5x + 10y = 13000
Dividing it by 5, we get
x + 2y = 2600 ..............(2)
Adding (1) and (2), we get
- x + 3y = 1400
x + 2y = 2600
______________
5y = 4000
______________
y = 4000/5
y = 800
Substituting the value of y = 800 in (2), we get
x + 2y = 2600
x + 2*800 = 2600
x + 2600 - 1600
x = 1000
So the cost price of tea set is Rs 1000 and the cost price of lemon set is Rs 800.
Answer
Let the cost of tea set be Rs 'x' and the cost of lemon set be Rs 'y'.
The shopkeeper sells a tea set at 5 % loss and a lemon set ate 15 % gain.
So, the loss on tea set = x*5/100
And the gain on lemon set = y*15/100
Total gain = 15y/100 - 5x/100 = 70
15y - 5x = 7000
Dividing it by 5, we get
3y - x = 1400
-x + 3y = 1400...........(1)
If he sells the tea set at 5 % gain and lemon set at 10 % gain, he gains Rs 130.
Therefore,
5x/100 + 10y/100 = 130
5x + 10y = 13000
Dividing it by 5, we get
x + 2y = 2600 ..............(2)
Adding (1) and (2), we get
- x + 3y = 1400
x + 2y = 2600
______________
5y = 4000
______________
y = 4000/5
y = 800
Substituting the value of y = 800 in (2), we get
x + 2y = 2600
x + 2*800 = 2600
x + 2600 - 1600
x = 1000
So the cost price of tea set is Rs 1000 and the cost price of lemon set is Rs 800.
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210
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