Question

On selling a tea-set at 5% loss and a lemon-set at 15% gain, a crockery seller gains Rs.7. If he sells the tea-set at 5% gain and the lemon-set at 10% gain he gains Rs.13. Find the actual price of the tea-set and the lemon-set.

Answer 1

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Answer 2

Answer:

The cost price of tea set is Rs 60 and the cost price of lemon set is Rs 100.

Step-by-step explanation:

Let x be the CP of tea-set and y be the CP of lemon-set.

According to Question,

Loss amount on tea set = $\frac{5}{100}\times x=\frac{x}{20}$

The gain on lemon set =  $\frac{10}{100}\times y=\frac{y}{10}$

Total gain,$\frac{y}{10}-\frac{x}{20}=7$

2y - x = 140 ..........(1)

Similarly for second situation,

$\frac{x}{20}+\frac{y}{10}=13$

x + 2y = 260 .........(2)

We solve both equations using elimination method,

Adding (1) and (2), we get

2y + 2y = 140 + 260

4y = 400

y = 100

Substituting the value of y = 100 in (2), we get

x + 2y = 260

x + 2 × 100 = 260

x + 200 = 260 

x = 60

So, The cost price of tea set is Rs 60 and the cost price of lemon set is Rs 100.