Question

One cubic plate having 15cm side floats on water surface. If Surface tension of water is 60dyne/cm. To lift this plate from water, find the extra force required against weight​

Answer 1

Explanation:

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Answer 2

Answer:

The force required to lift the plate from water is 3,600dyne/cm.

Explanation:

Given the side of a cubic plate floating on water surface, s = 15cm

Surface tension of water is 60dyne/cm

Surface tension(S) is defined as force(F) per unit length(L), which can be written as

$S=\dfrac{F}{L}$

Therefore, the force due to surface tension acts all along the surface length of the cubic plate.

Thus, the force required to lift the plate is equal to surface tension times the surface length. As the given plate is cubic, the surface length is the perimeter of the square.

And perimeter of the square is 4s.

Hence, the required force to lift the plate is

$F = S \times 4s$

$= 60 \times 4 \times 15 = 3,600 dyne/cm$

Therefore, the force required to lift the plate from water is 3,600dyne/cm.