Question

One mole of gas occupying 3 litre volume is expanded

Answer 1

Answer:

Work done = -P∆V

= - 1(15-3)

= -1×12

= -12 L-atm

= -1215.6 Joule

Answer 2

Answer:

The work done by a gas is equal to -1215.6 J

Solution :

This is the case of isothermal irreversible expansion of gas.

Formula used :

w=-P_{ext}\times (V_2-V_1)

where,

w = work done by the gas

P_{ext} = external pressure of gas = 1 atm

V_1 = initial volume of gas = 3 L

V_2 = final volume of gas = 15 L

Now put all the given values in the above formula, we get the work done.

w=-(1atm)\times (15L-3L)

w=-12Latm

w=-1215.6J

conversion : (1 L atm = 101.325 J)

Therefore, the work done by a gas is equal to -1215.6 J