One mole of KClO3 is heated in presence of MnO2. The produced oxygen is used in burning of Al. Then find no. of moles oxide of Al that will be formed .
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Potassium chlorate (KClO3) is used in the manufacture of oxygen in the presence of manganese oxide catalyst.
The reaction is as follows:
(heat in the presence of MnO2 catalyst)
2KClO3 -------------------------------------------------> 2KCl + 3O2
Therefore 2 moles of KClO3 produces 3 moles of oxygen.
Hence 1 mole of KClO3 will give 1.5 moles of oxygen. Using this to form AlO3 will give.;
2Al + 3O2 --------> 2AlO3
Therefore 3moles of O2 give 2moles of AlO3.
Hence 1.5moles will give (2x1.5)/3 = 3/3 = 1
AlO3 produced is 1mole
The reaction is as follows:
(heat in the presence of MnO2 catalyst)
2KClO3 -------------------------------------------------> 2KCl + 3O2
Therefore 2 moles of KClO3 produces 3 moles of oxygen.
Hence 1 mole of KClO3 will give 1.5 moles of oxygen. Using this to form AlO3 will give.;
2Al + 3O2 --------> 2AlO3
Therefore 3moles of O2 give 2moles of AlO3.
Hence 1.5moles will give (2x1.5)/3 = 3/3 = 1
AlO3 produced is 1mole
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