Question

One mole of monatomic gas is mixed with diatomic gas the value of

Answer 1

Answer:

Explanation:

For 1 mole of monoatomic gas

Cv = 3/2R

Cp = 5/2R

For 1 mole of diatomic gas

Cv = 5/2R

Cp = 7/2R

Cv = (3/2 +5/2)RT/2

Cp = (5/2 +7/2)RT/2

Cp/Cv =  γ = 3/2 RT

Hemce

γ = 1.5