Question

One mole of N,Hloses 10 mole of electrons to
form a new compound Y. Assuming that all
nitrogen appear in the new compound, what is
oxidation state of nitrogen? (there is no change
in the oxidation state of hydrogen)​

Answer 1

Answer: the oxidation state of Nitrogen in the new compund Y is +3

Explanation:

To begin , you will have to find the oxidation state of nitrogen in N2H4 . ( i think you copied your question wrong, hence i assumed you meant N2H4)

1. Oxidation state of Nitrogen in N2H4 is

• Since we do not know the oxidation state of Nitrogen  but we know the oxidation state of Hydrogen , we can do the following:
• replace the oxidation state of N by x since it is unknown and solve
• There are 2 Nitrogens and 4 Hydrogens  and the total oxidation state is 0 since there isn't a charge on the whole molecule.

• Hence                2(x) + 4(+1)= 0

                                   2x = -4

                                   x = -4/2

                                    x = -2  --> -2 is the oxidation state of Nitrogen in N2H4

      2.   2 Nitrogen  makes it -4 ,   they lose 10 electrons  

• 1 mole N2H4 loses 10mole e-  
• 1 N2H4 loses 10e-  
• new compound Y=(N2H4)10+  
• Charge on y is 10+
• Let charge on N be x.  
• 2x+4=10
• 2x =10-4
• 2x = 6
• x = 6/2
• x=+3