Question

one number is 1 more than7 times the other number if their sum is 73 more than twice the smaller number.find the number.

Answer 1

let one number= x

another number =7x+1
sum of these two = twice the smaller number +73
x +7x+1 =2x +73

8x+1=2x+73
8x-2x =73-1

6x =72

x= 72/6
x= 12
the number =x=12

Answer 2

Answer:

If their sum is 73 more than twice the smaller number [COMMA], find the numberS [PERIOD].

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