one number is 7 more than another and its square is 77 more than the square of the smaller number what are the numbers
Answers
Answered by
5
let the smaller number be x
then ,
(x +7)2 - x2 = 77
then ,
(x +7)2 - x2 = 77
Or x2 + 2*x*7 + 72 – 72 = 77
Or x2 +14x + 49 - 49 = 77
Or x2 +14x = 77
Or x2 +x = 77/14
Or x + x = ( 77 / 14)1/2
Or 2x = ( 77 / 14)1/2
Or x = ( 77 / 14)1/2 /2
Answered by
1
let one number be x
other no =x+7
(x+7)² -77 =x²
x²+49+14x-77=x²
x²-28+14x=x²
x²-x²+14x = 28
14x= 28
x= 2
other no = x+7 =2+7 =9
the numbers are 2 and 9
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