Math, asked by Dreamerboy, 1 year ago

one number is 7 more than another and its square is 77 more than the square of the smaller number what are the numbers

Answers

Answered by Geniusadarsh
5
let the smaller number be x
then ,
        (x +7)2 - x2 = 77

Or x2 + 2*x*7 + 72 – 72 = 77

Or x2 +14x + 49 - 49 = 77

Or x2 +14x = 77

Or x2 +x = 77/14

Or x + x = ( 77 / 14)1/2

Or 2x = ( 77 / 14)1/2

Or x = ( 77 / 14)1/2 /2 

Answered by manshvigajraj13
1

let one number be x

other no =x+7

(x+7)² -77 =x²

x²+49+14x-77=x²

x²-28+14x=x²  

x²-x²+14x = 28

14x= 28

x= 2  

other no = x+7 =2+7 =9

the numbers are 2 and 9

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