one number is 8 times than another the sume is 50 find the number
Madhu123mri:
There is an error in the question.
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Answered by
4
Let the 1st no. be x
And, the 2nd no. be 8x
Now,
x + 8x = 50
=> 9x = 50
=> x = 50/9
=> x = 5.5
And, the 2nd no. be 8x
Now,
x + 8x = 50
=> 9x = 50
=> x = 50/9
=> x = 5.5
The second number comes to be 44
Which is not possible
My answers are coming wrong
no you are right Bcoz it is made question by anyone.
The question is wrong
Answered by
0
Let the first number be 8x
Let another number be x
The sum= 50
x+8x= 50
9x= 50
x= 50/9
x= 5.5
The first number is 8×5.5= 44
The question seems wrong because this isn't possible.
Let another number be x
The sum= 50
x+8x= 50
9x= 50
x= 50/9
x= 5.5
The first number is 8×5.5= 44
The question seems wrong because this isn't possible.
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