Question

One number is three less than two times another. If their sum is increased by five the result is fourteen. Find the numbers

Answer 1

Answer:

let that unknown numbers be x and y respectively

as given per condition

$x^{2}$-3=y

Now it is given that there sum is 14 when increased by 5

i.e.,x+y+5=14

x+y=14-5

x+y=9

Now we want the numbers that sums 9 in place of x and y

So,if we take x=3 so our y=6

             $x^{2}$-3=y

            $3^{2}$-3=6

            9-3=6

            6=6

           LHS=RHS

Hence ,verified that two unknown numbers are 3 and 6

THANK YOU

Answer 2

Given : One number is three less than two times another. . If their sum is increased by five the result is fourteen.

To find : Numbers

Solution:

Let say two numbers are  M  & N

One number is three less than two times another

=> M  = 2N - 3

their sum  = M  + N

= 2N -3  + N

= 3N - 3

sum is increased by five the result is fourteen.

=> 3N - 3 + 5  = 14

=> 3N = 12

=> N = 4

M = 2N - 3

=> M = 2(4) - 3

=> M = 5

Numbers are  5  & 4

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