One of exterior angle of triangle is 105 degree and the interior opposite angles are in the ratio 2:5 find the angle of a tringle
onkarsingh0149:
75, 42 and 63
Answers
Answered by
41
TO FIND :-
Angles in a triangle whose exterior angle is 105° and interior opposite angles are in the ratio of 2:5
ANSWER :-
The angles in the triangle are 30°,75° and 75°
SOLUTION :-
Ratio = 2:5
Let the two angles be 2x and 5x
As we know that
Sum of two interior opposite angles = exterior angle
2x + 5x = 105
7x = 105
x = 105/7
x = 15°
Substituting x in 2x and 5x respectively
2x = 2(15) = 30°
5x = 5(15) = 75°
sum of angles in a triangle = 180°
30 + 75 + k = 180
105 + k = 180
k = 180 - 105
k = 75°
Angles in a triangle whose exterior angle is 105° and interior opposite angles are in the ratio of 2:5
ANSWER :-
The angles in the triangle are 30°,75° and 75°
SOLUTION :-
Ratio = 2:5
Let the two angles be 2x and 5x
As we know that
Sum of two interior opposite angles = exterior angle
2x + 5x = 105
7x = 105
x = 105/7
x = 15°
Substituting x in 2x and 5x respectively
2x = 2(15) = 30°
5x = 5(15) = 75°
sum of angles in a triangle = 180°
30 + 75 + k = 180
105 + k = 180
k = 180 - 105
k = 75°
Answered by
23
SEE THE ATTACHMENT FOR FIGURE.
SOLUTION:
ANGLE ACX=105°
AND AS WE KNOW
EXTERIOR ANGLE OF A TRIANGLE IS EQUAL TO THE SUM OF OPPOSITE ANGLES.
ANGLE ACX
=ANGLE ABC+ANGLE BAC
BUT IT IS GIVEN
ANGLE ABC/ANGLE BAC =2/5
SO
ANGLE ABC
=2/5 (ANGLE BAC)
HENCE
ANGLE ABC+ANGLE BAC =ANGLE ACX
ANGLE BAC
+(ANGLE BAC)2/5=105°
7(ANGLE BAC)/5=105°
ANGLE BAC=105°×5/7
ANGLE BAC=(15×5)°
ANGLE BAC =75°
ANGLE ABC=30°
ANGLE ACB=75°
thanks for asking
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