Question

one of the base angles of an isosceles triangle is 52 degree find its angle of vertex

Answer 1

We knw,
That in isosceles triangle, base angles are equal...
So,
In triangle ABC,
A+B+C=180°[Sum of angles of triangle is equal to 180°]
Or,52°+52°+C=180°
OR,104°+C=180°
C=76°


Hence angle of vertex=76°

Hope it helps
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Answer 2

Answer:

Step-by-step explanation:

we know in isosceles triangle, base angles are equal.

So,

In triangle ABC,  

A+B+C=180°[Sum of angles of triangle is equal to 180°]

Or,52°+52°+C=180°

OR,104°+C=180°

C=76°