One of the diagonals of a rhombus is 12cm sides area is 54 sq cm. the perimeter of the rhombus is
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area of rhombus is 1/2 of d1×d2 by applying this formula we get side as 9cm perimeter of the rhombus is 4×side so answer will be 36 if you like the answer please make it as brainlest
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Step-by-step explanation:
area of rhombus = ½ × d1 × d2 = 54 cm²
one diagonal = d1 = 12 cm
let the other diagonal be = x
the other diagonal = 9 cm
diagonal of rhombus bisects each other perpendicularly
it is divided into four right angled triangle
diagonal 1 => 1/2 × 12 = 6
diagonal 2 => 1/2 × 9 = 4.5
therefore the adjacent sides of right angle are 6cm and 4.5 cm
using Pythagoras theory we find the hypotenuse ( side of rhombus)
therefore the side of rhombus is = s = 7.5 cm
perimeter of rhombus = 4 x s
all sides of rhombus are equal
7.5 × 4 = 30 cm
the perimeter of rhombus is = 30 cm
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