one of the factors of x square-15x+56
Answers
Answered by
47
hello users ....
given quadratic equation is x²- 15x + 56 = 0
solution:-
x² - 15x + 56 = 0
=> x² -7x -8x + 56 = 0
=> x(x-7) - 8(x-7) = 0
taking (x-7) common..
=> (x-7)(x-8) = 0
=> (x - 7) and (x - 8) Are the two factors of given quadratic equation
and
x = 7 , 8 are the roots of equation
✴️⭐ hope it helps ⭐✴️
given quadratic equation is x²- 15x + 56 = 0
solution:-
x² - 15x + 56 = 0
=> x² -7x -8x + 56 = 0
=> x(x-7) - 8(x-7) = 0
taking (x-7) common..
=> (x-7)(x-8) = 0
=> (x - 7) and (x - 8) Are the two factors of given quadratic equation
and
x = 7 , 8 are the roots of equation
✴️⭐ hope it helps ⭐✴️
RehanAhmadXLX:
Ankit Bhaiya INBOX
yes
Now, correct
Answered by
25
Hi !!!
This is your answer...
Given Polynomial :- x² - 15x + 56
We have to find two numbers, a and b such a + b = -15 and ab = 56.
Factorising 56 = 2 X 2 X 2 X 7
= 8 X 7.
Clearly, two numbers a and b are 7 and 8.
x² - 8x - 7x + 56 = 0.
x (x-8) - 7 (x-8) = 0.
(x-7) (x-8) = 0.
Hence, two factors of given equation are x - 8 and x-7 .
Hope it helps...
This is your answer...
Given Polynomial :- x² - 15x + 56
We have to find two numbers, a and b such a + b = -15 and ab = 56.
Factorising 56 = 2 X 2 X 2 X 7
= 8 X 7.
Clearly, two numbers a and b are 7 and 8.
x² - 8x - 7x + 56 = 0.
x (x-8) - 7 (x-8) = 0.
(x-7) (x-8) = 0.
Hence, two factors of given equation are x - 8 and x-7 .
Hope it helps...
Similar questions