Question

One of the two digits of a two digit number is 3 times the other digit if you interchange the digit of these two digit number and at the resulting number to the original number you get 88 what is the original number ?

Answer 1

Hi.

Here is your answer---

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Let the once digit of a two-digit number be y and tens digit be x.

Thus, Original Number = 10x + y

According to the Questions,

  x = 3 × y ------------------------eq(i)

If we interchange the digits, then

New Number = 10y + x

Also,
    10x + y + 10y + x = 88
    11x + 11y = 88
           x + y = 8 -------------------------------eq(ii)

Putting the Values of eq(i) in to eq(ii),

   3y + y = 8
     4y = 8
      y = 2

Putting y =  in eq(i),
   x = 3 × 2
   x = 6

Original Number = 10x + y
                            = 10(6) + 2
                            = 60 + 2
                            = 62

Thus, the original Two-Digits number is 62.

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Hope it helps.

Have a nice day.