one shot is fired from each of the three guns Let ABC denotes the event that the target is hit by the first second and third respectively. Assuming that ABC are independent events and that P(A)=0.5P(B)=0.6P(C)=0.8.Find the probability that at least one hit is registered
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Answered by
1
P(E)=0.5+0.6+0.8÷3
=1.9÷3
=0.6333
=1.9÷3
=0.6333
Answered by
3
p(atleast 1)= 1-p(none hit the target)
= 1- (1-p(A))(1-p(B))(1-p(C))
= 1-(1-0.5)(1-0.6)(1-0.8)
=1-(0.5)(0.4)(0.2)
=1-(0.04)
=0.96
= 1- (1-p(A))(1-p(B))(1-p(C))
= 1-(1-0.5)(1-0.6)(1-0.8)
=1-(0.5)(0.4)(0.2)
=1-(0.04)
=0.96
vivek242:
this is the right answer
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