Math, asked by vivek242, 1 year ago

one shot is fired from each of the three guns Let ABC denotes the event that the target is hit by the first second and third respectively. Assuming that ABC are independent events and that P(A)=0.5P(B)=0.6P(C)=0.8.Find the probability that at least one hit is registered

Answers

Answered by pihu74
1
P(E)=0.5+0.6+0.8÷3
=1.9÷3
=0.6333



Answered by nicko1
3
p(atleast 1)= 1-p(none hit the target)
= 1- (1-p(A))(1-p(B))(1-p(C))
= 1-(1-0.5)(1-0.6)(1-0.8)
=1-(0.5)(0.4)(0.2)
=1-(0.04)
=0.96

vivek242: this is the right answer
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