Question

One side of a rectangular field is 15m and one of its diagonal is 17m.
Find the area of the field.

Please help me in this question​

Answer 1

Step-by-step explanation:

Let ABCD be a rectangle

AB=15m

BD= 17m

In ∆ABD

AD=√289-225

AD=√64

AD=8m

Area of rectangle ABCD

length×breadth

15×8

120 m sq.

Answer 2

Given:

• One side of rectangular field = 15 m
• One Diagonal of rectangular field = 17 m

To find:

• Area of rectangular field?

Solution:

• Let's consider ABCD is a rectangle.

Where,

• Hypotenus = Diagonal = 17 m
• Base = Length = 15 m
• Perpendicular = Breadth

• Let Breadth of rectangle be b m.

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, By using Pythagoras Theorem,

→ (Hypotenus)² = (Perpendicular)² + (Base)²

→ (17)² = b² + (15)²

→ 289 = b² + 225

→ b² = 289 - 225

→ b² = 64

→ √b² = √64

→ b = 8 m

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Let's Find Area of rectangular field,

As we know that,

• Area of rectangle = Length × Breadth

→ Area = 15 × 8

→ Area = 120 m²

∴ Hence, Area of rectangular field is 120 m².