One side of a right triangle of hypotenuse 20 cm is 16 cm area of a triangle is-
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AC=20 cm
AB=16 cm
by Pythagoras theorem
AC^2=AB^2 + BC^2
20^2 -16^2 =BC^2
144=Bc^2
BC=12
Area of triangle ABC=1/2×16 ×12=96
AB=16 cm
by Pythagoras theorem
AC^2=AB^2 + BC^2
20^2 -16^2 =BC^2
144=Bc^2
BC=12
Area of triangle ABC=1/2×16 ×12=96
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one side of a right triangle of hypotenuse 20cm is 16cm area of the triangle is:
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