One side of a triangle is 15 inches, and the area of the triangle is 90 sq. inches. Find the area of a similar triangle in which the corresponding side is 9 inches.
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now the ratio of area of two similar triangles is equal to the ratio of the squares of their corresponding sides
by the above statement
let x be the area of the second triangle
90/x=(15)^2/(9)^2
90/x=225/81
225x=90x81
x=(90×81)/225
x=32
AREA of the similar triangle is 32 Sq.inches
by the above statement
let x be the area of the second triangle
90/x=(15)^2/(9)^2
90/x=225/81
225x=90x81
x=(90×81)/225
x=32
AREA of the similar triangle is 32 Sq.inches
karlaleggettoyp7lv:
close very close
by .2
im mean .4
Answered by
0
Answer:
32.4
Step-by-step explanation:
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