Only 8th number of two different dice
Attachments:
Answers
Answered by
1
the answer is 10 chances
karthikeya61:
pls mark me branilist
Answered by
1
Solution==>
Total outcomes=36
Sample Space=
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Probability=Favourable outcomes/Total outcomes
a)P(10)=
sample Space=(4,6)(5,5)(6,4)
==>3/36==>1/12
b)P(equal to or less then 10)=If 10 or less is winning then 11 and 12 are losing. The only way to get 11 or 12 would be (5,6) (6,5) and (6,6). That makes three losers so 36 -3 = 33, there are 33 outcomes
sample space=36-3=33
==>33/36=11/12
ANSWER....
Total outcomes=36
Sample Space=
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Probability=Favourable outcomes/Total outcomes
a)P(10)=
sample Space=(4,6)(5,5)(6,4)
==>3/36==>1/12
b)P(equal to or less then 10)=If 10 or less is winning then 11 and 12 are losing. The only way to get 11 or 12 would be (5,6) (6,5) and (6,6). That makes three losers so 36 -3 = 33, there are 33 outcomes
sample space=36-3=33
==>33/36=11/12
ANSWER....
it is correct
yes
plz mark it as BRAINLIEST
Similar questions