Question

only Genius can answer

Answer 1

❤ Saiyaan ❤

Well I'm not genius, but I will surely answer this!

Given,

H = 5m

We have,

u = 0

t = T

Now,

Apllying equation of motion,

S = ut + 1/2*a*t^2

5 = 1/2*a*T^2.........(1)

Now for 2nd drop,

t = T/2

Applying equation of motion,

h = 1/2*a*T^2/4........ (2)

Now,

Just divide 2 by 1,

h = 1.25m

Therefore,

H - h = 3.75m

♥ Saiyaan ♥

Answer 2

let T be the time taken by first drop to reach the ground,then from relation:

s = ut+1/2at^2

Here s=5m, u=0 and t=T..........(i)

Time taken by second drop will be T/2 ,therefore its distance from tap:

h=0+1/2aT^2/4...........(ii)

Dividing (i) and (ii)

h/5 = 1/4

or, h=1.25m

therefore, H-h= 5-1.25=3.75m

hence option (c) is correct

hope it helps you........