Question

Or question pls do


In the following fig.....

Answer 1

so here is your answer....

join OC, OD and BD

∆ODC is an equilateral

therefore, angle COD=60°

Now, angle CBD=1/2angle COD (angle subtended by an arc at center is twice angle subtended by it at remaining part of circle)

so, angle CBD=30°

again, angle ACB=90°(angle on semicircle)

so, angle BCE=180°-angle ACB

=90°

in∆CBE

angle BCE+angle CHE+angle CAN=180°

angle CEB=180°-90°+30°

angle AE=60°... ans.

★★★Hope it will be helpful for you★★★