origin divides join of point (1,1) and (2,2) externally in ratio
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0
Answer:
The points are (x
1
,y
1
)=(0,0)and(x
2
,y
2
)=(1,2)
∴ The ordinate of the point, which divides the line joining the points.
(x
1
,y
1
)and(x
2
,y
2
) in a ratio m
1
:m
2
externally is
Y=
m
1
−m
2
m
1
y
2
−m
2
y
1
Given that m
1
=3 & m
2
=2
∴Y=
3−2
3×2−2×0
=6
Answered by
0
ANSWER:
Hence the ratio is 1:2
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