Question

out of 1900 km vishal travelled some distance by bus and some by aeroplane. bus travels with average speed of 60km/hr and the average speed of aeroplane is 700km/hr. it takes the 5 hurs to complete the journey. find the distance vishal traveled by bus?

Answer 1

Let Vishal travelled x km distance by bus and (1900 - x) km distance by aeroplane.

speed of bus = 60 km/h
speed of aeroplane = 700 km/h
total time taken to complete = 5 hrs

∵ time = distance/speed
∴ total time taken to complete = time taken to travel by bus + time taken to travel by aeroplane
⇒ 5hrs = x/60 + (1900 - x)/700
⇒5 = (70x + 1900 × 6 - 6x)/4200
⇒5 = (64x + 11400)/4200
⇒5 × 4200 = 64x + 11400
⇒21000 = 64x + 11400
⇒21000 - 11400 = 64x
⇒9600 = 64x
⇒x = 150 km

Hence, distance travelled by bus = 150 km
and distance travelled by aeroplane = 1900 - 150 = 1750 km

Answer 2

Hello Dear.

Here is your answer---


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Let the distance traveled by the bus be a km.

Thus, distance traveled by the Aeroplane = (19000 - a) km.

For the Bus,
 Speed of the Bus = 60 km/hr.
 Distance Traveled = a km.

Using the Formula,
           Speed = Distance/Time
           Time(T₁) = a/60 km/hr.

For the Aeroplane,

 Speed of the Aeroplane= 700 km/hr.
     Distance = (1900-a) km

Thus, time(T₂) = (1900 - a)/700

According to the Question,
 
                              T₁ + T₂ =  5 hours.
                    $\frac{a}{60} + \frac{1900-a}{700} = 5$  
                     
   Taking L.C.M.
        $\frac{ 70a + 11400 - 6a}{4200} = 5$
     
   ⇒            64a + 11400 = 5 × 4200
                      64a = 21000 - 11400
                        64a = 9600
                   ⇒ a = 150 km

Thus, the distance traveled by the Bus is 150 km.

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Hope it helps.


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