Question

out of H2SO4 AND H3PO4, WHICH ONE IS MORE EFFECTIVE IN CAUSING COAGULATION OF POSITIVELY CHARGED SOL GIVE REASON.

Answer 1

I am not sure if you have any questions or concerns please visit the plug-in settings of your question about the same to you and your family and friends is the best way to the answer is yes then please let me know if you have any questions or concerns please visit the plug-in settings of your question about the same to you and

Answer 2

Answer: $H_3PO_4$

Explanation:

The given sol is positively charged. In order to bring about the coagulation oppositely charged ions must be added.

According to Hardy Schulze rule, greater the charge on the oppositely charged ion of the electrolyte added, more effective is the coagulation. Thus to coagulate a positively charged colloid, we must see the negatively charged ions.

$H_2SO_4$ contains $SO_4^{2-}$ ions and $H_3PO_4$ contains $PO_4^{3-}$ ions.

Thus $PO_4^{3-}$ ions bearing the higher negative charge is more effective in bringing the coagulation of positively charged sol.