Oxidation state of Fe in Mohr's salt..
Answers
Answered by
23
The formula of the Mohr salt is written as follows:
FeSO4 (NH4)2SO4.6H2O
The total molar mass of the substance is calculated as follows:
You should add up the molecular mass of the elements contained in the compounds.
The total weight is about 392 g per mol.
Looking at the formula one can say that Oxidation number of NH4 ion is +1
The oxidation number of SO4 ion is -2
Oxidation number of hydrogen ion is +1
Oxidation number of oxygen is
-2 X + 2(+1) + 2(-2) + 6[2(1) - 2]
= 0 X + 2 - 4 + 6[2 - 2]
= 0 X - 2 + 6(0)
= 0 X - 2 + 0 = 0 X - 2
= 0 X = 2
Hence oxidation number of Fe is +2
Therefore the new name is Ammonium iron (II) tetraoxosulphate (VI) hexahydrate salt
FeSO4 (NH4)2SO4.6H2O
The total molar mass of the substance is calculated as follows:
You should add up the molecular mass of the elements contained in the compounds.
The total weight is about 392 g per mol.
Looking at the formula one can say that Oxidation number of NH4 ion is +1
The oxidation number of SO4 ion is -2
Oxidation number of hydrogen ion is +1
Oxidation number of oxygen is
-2 X + 2(+1) + 2(-2) + 6[2(1) - 2]
= 0 X + 2 - 4 + 6[2 - 2]
= 0 X - 2 + 6(0)
= 0 X - 2 + 0 = 0 X - 2
= 0 X = 2
Hence oxidation number of Fe is +2
Therefore the new name is Ammonium iron (II) tetraoxosulphate (VI) hexahydrate salt
Answered by
4
Answer:
it is +2 oxidation
Explanation:
go by simple steps
i have attached the pic with is
i hope it will help u
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