Chemistry, asked by Bidyapb838, 10 months ago

Oxidising power of chlorine in aqueous solution can be
determined by the parameters indicated below:
1/2 Cl₂(g)□(→┴(1/2 ∆dissH) )Cl (g)□(→┴(1/2 ∆dissH) )Cl⁻(g)
□(→┴∆HydH )Cl⁻(aq)
(using the data, ∆diss HCl₂ = 240 kJ mol⁻¹,
∆eg H Cl = –349 kJ mol⁻¹, ∆hyd HCl⁻ = –381 kJ mol⁻¹),
will be
(a) + 152 kJ mol⁻¹ (b) – 610 kJ mol⁻¹
(c) – 850 kJ mol⁻¹ (d) + 120 kJ mol⁻¹

Answers

Answered by Anonymous
0

\huge\bold\red{Answer:-}

(a) + 152 kJ mol⁻¹

Answered by ItzSmartyYashi
0

\huge{\underline{\mathbb{\red{Answer}}}}

(a) + 152 kJ mol⁻¹

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