Question

P= (2, 4, 6, 8,9) and a = (1,3,6,7,9) then find
PUQ, PnQ, P-Q and Q-P.​

Answer 1

Step-by-step explanation:

p=2,4,6,8,9

a=1,3,6,7,9

• pUQ=(6,9)

1. explanation:in p and Q numbers which are same that will be consider as put

• .PnQ=(2,4,8,1,3,7,)
• explanation:in p and Q which are different that will be consider
• p-Q=(2,4,8)
• Q-p=1,3,7

Answer 2

Correct question is,

P= {2, 4, 6, 8,9} and Q = {1,3,6,7,9} then find

PUQ, P and Q, P-Q, and Q-P.

The values of PUQ, P and Q, P-Q, and Q-P are given below,

Given,

P={2,4,6,8,9}

Q={1,3,6,7,9}

To find,

PUQ, P and Q, P-Q, and Q-P.

Solution,

We have to find the union, intersection, and difference of the given sets.

PUQ

To find the union of the given sets, we will take all the elements of the sets.

PUQ={1,2,3,4,6,7,8,9}

and

To find the intersection of the sets, we have to find the elements which are common in both sets.

P and Q={6,9}

P-Q and Q-P,

To get the subtraction of the sets, we will subtract the elements of the second which are common with the first set from that on the first set.

P-Q={2,4,8}

Q-P={{1,3,7}.

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