Question

(p-3)^2 -(q+1)^2 is same as

Options are
a) p^2-q^2-10
b)(p-3)^2-q^2-1
c)(p-q+2)(p-q+4)
d)(p-q-4)(p+q-2)

Answer 1

Answer:

4

Use

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(p - 3 + q + 1)(p - 3 - q - 1) = (p + q - 2)(p + q - 4)$