Question

P=62500,N=2year,6month,R=12% per annul compounded annually​

Answer 1

$given \\ p = 62500 \\ n = 2 \\ r = 12\% \\ the \: compound \: interest \: is : \\ p {(1 + \frac{r}{100}) }^{n} \\ = 62500 {(1 + \frac{12}{100} })^{2} \\ = 62500 {( \frac{112}{100} )}^{2} \\ = 62500 \times \frac{112}{100} \times \frac{112}{100} \\ = 625 \times 112 \times \frac{112}{100} \\ = 78400$

the compound interest is ,

78400 ✔✔✔✔

✨✨hope it helps✨✨