p a intersection b c people to a minus b
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P(B)=16∗P(A) ……( 1)
P(Ac∩Bc)=1−P(A∪B)=1−[P(A)+P(B)−P(À∩B)]
⇒13=1−P(A)−P(B)+16
⇒P(A)+P(B)=1+16−13=56
⇒P(A)+16∗P(A)=56
⇒6P(A)2−5P(A)+1=0
⇒6P(A)2−3P(A)−2P(A)+1=0
⇒[2P(A)−1][3P(A)−1]=0
⇒P(A)=12or 13
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