P(A' intersection B') formula
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lets say I have a switch A with 3 legs, each leg has 0.8 chance to be connected (and then electricity will flow), we need only 1 leg connected for A to transfer the electricity (so sorry I didn't explain it that well I'm having hard time to translate this problem)
So I calculated the chance of A to transfer electricity by doing 1−(0.2)31−(0.2)3 which is 124125124125 which I think is true.
The problem is I wanted to say that A will transfer elecricity only if 1 of his legs will be connected so its like saying 0.8+0.8+0.80.8+0.8+0.8 which is obviously wrong(over 11) so I used the weird formula that says to do like this: 0.8+0.8+0.8−(0.8)2−(0.8)2−(0.8)2+(0.8)3=1241250.8+0.8+0.8−(0.8)2−(0.8)2−(0.8)2+(0.8)3=124125too.
So I calculated the chance of A to transfer electricity by doing 1−(0.2)31−(0.2)3 which is 124125124125 which I think is true.
The problem is I wanted to say that A will transfer elecricity only if 1 of his legs will be connected so its like saying 0.8+0.8+0.80.8+0.8+0.8 which is obviously wrong(over 11) so I used the weird formula that says to do like this: 0.8+0.8+0.8−(0.8)2−(0.8)2−(0.8)2+(0.8)3=1241250.8+0.8+0.8−(0.8)2−(0.8)2−(0.8)2+(0.8)3=124125too.
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